(-2.4x^2)+1.4=0

Solution for (-2.4x^2)+1.4=0 equation:

(-2.4x^2)+1.4=0

We get rid of parentheses

-2.4x^2+1.4=0

a = -2.4; b = 0; c = +1.4;
Δ = b2-4ac
Δ = 02-4·(-2.4)·1.4
Δ = 13.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{13.44}}{2*-2.4}=\frac{0-\sqrt{13.44}}{-4.8}
=-\frac{\sqrt{}}{-4.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{13.44}}{2*-2.4}=\frac{0+\sqrt{13.44}}{-4.8}
=\frac{\sqrt{}}{-4.8}
$